Eng.Saeed Almalowi
Posts : 38 Join date : 2009-10-27 Location : UNITED STATE OF AMERICA, STATE COLLEGE,PA
| Subject: EQUIVALENT RESISTANCE FOR PARALLEL CIRCUITS Wed Nov 04, 2009 9:15 am | |
| Find the equivalent resistance for the circuit shown above.Note that the 4 and 5 are NOT in parallel because the 2 and 8 are in between. The 1 and 2 are NOT in series because the 4 is in between. The 1 and 7 are NOT in parallel because the 4 is in between. The only combination you can make (at first) is the 3, 6, and 9 are in series, so: Now the 5 and 18 are in parallel: The 2, 3.9, and 8 are in series: The 4 and 13.9 are in parallel: Finally, all three are in series Req = 1 + (4 || {2 + [5 || (3+6+9)] + 8}) + 7 = 11.1 ohms | |
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