ENGINEERING COURSES FOR UNDERGRADUATE STUDENTS

LECTURES & APPLICATIONS
 
HomeHome  CalendarCalendar  FAQFAQ  SearchSearch  MemberlistMemberlist  UsergroupsUsergroups  RegisterRegister  Log inLog in  

Share | 
 

 EQUIVALENT RESISTANCE FOR PARALLEL CIRCUITS

Go down 
AuthorMessage
Eng.Saeed Almalowi



Posts : 38
Join date : 2009-10-27
Location : UNITED STATE OF AMERICA, STATE COLLEGE,PA

PostSubject: EQUIVALENT RESISTANCE FOR PARALLEL CIRCUITS   Wed Nov 04, 2009 9:15 am

Find the equivalent resistance for the circuit shown above.

Note that the 4 and 5 are NOT in parallel because the 2 and 8 are in between. The 1 and 2 are NOT in series because the 4 is in between. The 1 and 7 are NOT in parallel because the 4 is in between. The only combination you can make (at first) is the 3, 6, and 9 are in series, so:

Now the 5 and 18 are in parallel:

The 2, 3.9, and 8 are in series:

The 4 and 13.9 are in parallel:
Finally, all three are in series

Req = 1 + (4 || {2 + [5 || (3+6+9)] + 8}) + 7

= 11.1 ohms
Back to top Go down
View user profile http://www.aalhameed1.net
 
EQUIVALENT RESISTANCE FOR PARALLEL CIRCUITS
Back to top 
Page 1 of 1
 Similar topics
-
» Gods and Goddesses : Danu
» Palmistry
» 50% SINGLE LARGEST CONTRACT
» Any other natural products or alternatives to Optifast that someone can recommend?
» CERN: Scientists Talk Of 'Parallel Universes, Extra Dimensions'

Permissions in this forum:You cannot reply to topics in this forum
ENGINEERING COURSES FOR UNDERGRADUATE STUDENTS :: ELECTRICAL ENGINEERING FORUM :: FUNDAMENTAL OF ELECTRICAL CIRCUITS FORUM-
Jump to: